∇ · E = ρ/ε₀
∇ × E = −∂B/∂t
∇ · B = 0
∇ × B = μ₀J + μ₀ε₀(∂E/∂t)
iℏ(∂Ψ/∂t) = ĤΨ
Ĥ = −(ℏ²/2m)∇² + V(r,t)
X(f) = ∫ x(t) e^(−i2πft) dt
x(t) = ∫ X(f) e^(i2πft) df
ρ(∂u/∂t + u · ∇u) = −∇p + ∇ · τ + ρg
H(X) = −∑ P(x) log₂ P(x)
f(x) = (1/σ√2π) e^[−½((x−μ)/σ)²]
∂L/∂q − (d/dt)(∂L/∂q̇) = 0
L = T − V
f(x) = ∑ [fⁿ(a)/n!] (x − a)ⁿ
eˣ = 1 + x + x²/2! + x³/3! + ...
P(A|B) = [P(B|A) P(A)] / P(B)
dS = δQ / T
ΔS_universe ≥ 0
A v = λ v
det(A − λI) = 0
e^(iπ) + 1 = 0
Clarity in every
problem set.
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